Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Appendix A - Basic Algebra Review - A Exercises - Page A-15: 61

Answer

$\frac{25}{9} $.

Work Step by Step

The given expression is $=\frac{2}{3} \left (\frac{5}{2}+\frac{7}{3} \right )-\left ( \frac{2}{3} \right )^2$ Get a common denominator inside parentheses first. $=\frac{2}{3} \left (\frac{15}{6}+\frac{14}{6} \right )-\left ( \frac{2}{3} \right )^2$ Add numerators inside parentheses. $=\frac{2}{3} \left (\frac{29}{6} \right )-\left ( \frac{2}{3} \right )^2$ Multiply. $=\frac{29}{9} -\left ( \frac{2}{3} \right )^2$ Calculate the exponent. $=\frac{29}{9} - \frac{4}{9}$ Subtract numerators because denominators are same. $=\frac{25}{9} $.
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