Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Appendix A - Basic Algebra Review - A Exercises - Page A-15: 84

Answer

$r=-\frac{4}{9}$.

Work Step by Step

The given expression is $\Rightarrow \frac{3}{8}r+\frac{5}{6}=\frac{2}{3}$ Multiply by the LCD =24. $\Rightarrow 24\left ( \frac{3}{8}r+\frac{5}{6} \right )=24\left (\frac{2}{3}\right )$ Use distributive property. $\Rightarrow 24\left ( \frac{3}{8}r\right )+24\left ( \frac{5}{6} \right )=24\left (\frac{2}{3}\right )$ Simplify. $\Rightarrow 9r+20=16$ Subtract $20$ from both sides. $\Rightarrow 9r+20-20=16-20$ Simplify. $\Rightarrow 9r=-4$ Divide both sides by $9$. $\Rightarrow \frac{9r}{9}=\frac{-4}{9}$ Simplify. $\Rightarrow r=-\frac{4}{9}$.
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