Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Appendix A - Basic Algebra Review - A Exercises - Page A-15: 82

Answer

$h=16$

Work Step by Step

Step 1: $\frac{3}{8}h+7=13$ Step 2: Subtract 7 from both sides: $\frac{3}{8}h+7-7=13-7$. Step 3: $\frac{3}{8}h=6$ Step 4: Multiply both sides by 8: $\frac{3}{8}h\times8=6\times8$. Step 5: $3h=48$ Step 6: Divide both sides by 3: $\frac{3h}{3}=\frac{48}{3}$. Step 7: $h=16$
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