Answer
$x=2e$
Work Step by Step
Using the properties of logarithms and since $\log_b x=y$ is equivalent to $b^y=x$, then,
\begin{array}{l}
\ln x-\ln 2=1\\\\
\ln \dfrac{x}{2}=1\\\\
\log_e \dfrac{x}{2}=1\\\\
\dfrac{x}{2}=e^1\\\\
x=2e
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 9 - Review - Page 598: 129
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
