Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Review - Page 598: 121

Answer

$x=\dfrac{11}{9}$

Work Step by Step

Express both sides of the equation with the same base. Once the bases are the same, then equate the exponents. That is, \begin{array}{l} 8^{3x-2}=32\\\\ (2^3)^{3x-2}=2^5\\\\ 2^{9x-6}=2^5\\\\ 9x-6=5\\\\ 9x=11\\\\ x=\dfrac{11}{9} .\end{array}
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