Answer
$x=2\sqrt{2}$
Work Step by Step
Using properties of logarithms, then,
\begin{array}{l}
\log_2 x+\log_2 2x-3=1\\
\log_2 x+\log_2 2x=4\\
\log_2 [x(2x)]=4\\
x(2x)=2^4\\
2x^2=16\\
x^2=8\\
x=\sqrt{8}\\
x=2\sqrt{2}
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 9 - Review - Page 598: 109
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
