Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Review - Page 598: 117

Answer

$x\approx0.69$

Work Step by Step

Taking the natural logarithm of both sides, the value of $x$ in the expression $ e^x=2 $ is, \begin{array}{l} \ln e^x=\ln2\\ x\ln e=\ln2\\ x(1)=\ln2\\ x=\ln2\\ x\approx0.69 .\end{array}
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