Intermediate Algebra (6th Edition)

$2x^{2}-9x-5$
We are given that $f(x)=x-5$ and $g(x)=2x+1$. We know that $(f\times g)(x)=f(x)\times g(x)$. Therefore, $(f\times g)(x)=f(x)\times g(x)=(x-5)(2x+1)$. We can use the FOIL method to simplify. F=$(x\times2x)=2x^{2}$ O=$(x\times1)=x$ I=$(-5\times2x)=-10x$ L=$(-5\times1)=-5$ Next, we can add these terms together. $(2x^{2})+(x)+(-10x)+(-5)=2x^{2}-9x-5$