Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Review - Page 596: 34

Answer

$x=\frac{3}{2}$

Work Step by Step

We are given that $5^{2x}=125$. Both of these numbers are powers of 5, so we can rewrite the equation as $5^{2x}=5^{3}$. From the uniqueness of $b^{x}$, we know that $b^{x}=b^{y}$ is equivalent to $x=y$ (when $b\gt0$ and $b\ne1$). Therefore, $2x=3$. To solve for x, divide both sides by 2. $x=\frac{3}{2}$
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