Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Review: 16a

Answer

1

Work Step by Step

We are given that $f(x)=\sqrt(x+2)$ is a one-to-one function. To find the value of $f(-1)$, we can plug -1 into the given function. $f(-1)=\sqrt(-1+2)=\sqrt(1)=1$
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