Answer
$x^{2}-1$
Work Step by Step
We are given that $f(x)=x^{2}-2$, $g(x)=x+1$, and $h(x)=x^{3}-x^{2}$.
We know that $(g\circ f)(x)=g(f(x))$.
Therefore, $(g\circ f)(x)=g(f(x))=g(x^{2}-2)=(x^{2}-2)+1=x^{2}-1$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 9 - Review - Page 596: 6
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