Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Cumulative Review: 28b

Answer

$2a$

Work Step by Step

$\frac{\sqrt {108a^{2}}}{3\sqrt 3}$ =$\frac{\sqrt {3\times36\times a^{2}}}{3\sqrt 3}$ =$\frac{\sqrt {3}\times \sqrt {36\times a^{2}}}{3\sqrt 3}$ =$\frac{\sqrt {3}\times 6a}{3\sqrt 3}$ =$\frac{6a}{3}$ =$2a$
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