Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Cumulative Review: 26a

Answer

$a-a^{2}$

Work Step by Step

We can use the product rule to simplify, which holds that $a^{m}\times a^{n}=a^{m+n}$ (where a is a real number, and m and n are positive integers). $a^{\frac{1}{4}}(a^{\frac{3}{4}}-a^{\frac{7}{4}})=(a^{\frac{1}{4}}\times a^{\frac{3}{4}})-(a^{\frac{1}{4}}\times a^{\frac{7}{4}})=(a^{\frac{1}{4}+\frac{3}{4}})-(a^{\frac{1}{4}+\frac{7}{4}})=a^{\frac{4}{4}}-a^{\frac{8}{4}}=a-a^{2}$
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