Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Cumulative Review: 24a

Answer

3

Work Step by Step

$\sqrt[3] 27=3$, which we know because $3^{3}=3\times3\times3=27$
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