Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Cumulative Review: 24d



Work Step by Step

$\sqrt[4] (x^{12})=x^{3}$, which we know because $(x^{3})^{4}=x^{3\times4}=x^{12}$
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