Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set: 7

Answer

-6

Work Step by Step

$\sqrt 36=6$, because $(6)^{2}=(6\times6)=36$ By adding a negative sign in front of $\sqrt 36$, we are taking the negative of $\sqrt 36$, which is $-(6)=-6$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.