Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 416: 28

Answer

$-4x^{2}$

Work Step by Step

$\sqrt[3] (-64x^{6})=-4x^{2}$, because $(-4x^{2})^{3}=-4x^{2}\times -4x^{2}\times -4x^{2}=(-4\times-4\times-4)\times x^{2+2+2}=-64x^{6}$
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