Answer
$4y^{3}$
Work Step by Step
$\sqrt (16y^{6})=4y^{3}$, because $(4y^{3})^{2}=4y^{3}\times 4y^{3}=(4\times4)\times(y^{3}\times y^{3})=16y^{6}$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 416: 11
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