Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set: 26

Answer

$x^{15}$

Work Step by Step

$\sqrt[3] (x^{15})=x^{5}$, because $(x^{5})^{3}=x^{5}\times x^{5}\times x^{5}=x^{5+5+5}=x^{15}$
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