Answer
$x^3-9x=x(x-3)(x+3)$
Work Step by Step
Factor out the GCF $x$ to have:
$=x(x^2-9)$
Factor the difference of two squares to have:
$=x(x-3)(x+3)$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 6 - Section 6.4 - Dividing Polynomials: Long Division and Synthetic Division - Exercise Set - Page 371: 69
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