Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.4 - Dividing Polynomials: Long Division and Synthetic Division - Exercise Set - Page 371: 59

Answer

$x=2$

Work Step by Step

Subtract $4x$ and add $4$ to both sides f the equation to have: $x^2-4x+4=4x-4-4x+4 \\x^2-4x+4=0$ Factor the trinomial to have: $(x-2)(x-2)=0$ Equate eachunique factor to zero then solve each equation to have: $x-2=0 x=2$ Thus, the solution is $x=2$.
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