Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.4 - Dividing Polynomials: Long Division and Synthetic Division - Exercise Set - Page 371: 60

Answer

$x=1 \text{ or } x=-3$

Work Step by Step

Subtract $4x$ and add $4$ to both sides f the equation to have: $5x^2+10x-15=15-15 \\5x^2+10x-15=0 \\5(x^2+2x-3)=0$ Divide 5 to both sides of the equation to have: x^2+2x-3=04 Factor the trinomial to have: $(x-1)(x+3)=0$ Equate each unique factor to zero then solve each equation to have: $x-1=0 \text{ or } x+3=0 \\x=1 \text{ or } x = -3$
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