Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.4 - Dividing Polynomials: Long Division and Synthetic Division - Exercise Set - Page 371: 67

Answer

$xy+2x+3y+6=(y+2)(x+3)$

Work Step by Step

Regroup to have: $=(xy+2x)+(3y+6)$ Factor out the GCF $x$ in the first group and $3$ in the second group to have: $=x(y+2)+3(y+2)$ Factor out the GCF $(y+2)$ to have: $=(y+2)(x+3)$
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