## Intermediate Algebra (6th Edition)

$$h=\frac{11}{2}$$ $$b=6$$
Let $x$ be the width, then $$h=x$$ $$b=2x-5$$ $$b*h=(2x-5)(x)=33$$ $$2x^2-5x=33$$ $$2x^2-5x-33=0$$ $$(2x-11)(x+3)=0$$ Solving each parenthesis 1)$$2x-11=0$$ $$x=\frac{11}{2}$$ 2) $$x+3=0$$ $$x=-3$$ As lenght can not be negative then the value of $x$ is $\frac{11}{2}$ $$h=\frac{11}{2}$$ $$b=2*\frac{11}{2}-5=6$$