Answer
$$x=0$$ $$x=6$$ $$x=-3$$
Work Step by Step
We have $$x^3-18x=3x^2$$
Sending all the terms to the left side of the equation $$x^3-18x-3x^2=0$$
Factorizing $$x(x^2-3x-18)=0$$ $$x(x-6)(x+3)=0$$
Solving each parenthesis 1)$$x=0$$
2)$$x-6=0$$ $$x=6$$
3)$$x+3=0$$ $$x=-3$$
