## Intermediate Algebra (6th Edition)

$x=-3$ and $x=4$ and $x=-\frac{1}{5}$
$6(x+3)(x-4)(5x+1)=0$ Using the Zero Product Property $6=0$ and $x+3=0$ and $x-4=0$ and $5x+1=0$ The first equation $6=0$ is false. The second equation: $x+3=0$ Subtract $3$ from both sides $x=-3$ The third equation $x-4=0$ Add $4$ to both sides $x=4$ The fourth equation $5x+1=0$ Subtract $1$ from both sides $5x=-1$ Divide by $5$ $x=-\frac{1}{5}$