## Intermediate Algebra (6th Edition)

$$x=-\frac{15}{2}$$ $$x=7$$
Let $x$ be the number $$x+2x^2=105$$ $$2x^2+x-105=0$$ $$(2x+15)(x-7)=0$$ Solving each parenthesis 1)$$2x+15=0$$ $$x=-\frac{15}{2}$$ 2)$$x-7=0$$ $$x=7$$