Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review: 8

Answer

$\frac{1}{16}$

Work Step by Step

$(-4)^{-2}=(\frac{1}{(-4)^{2}})=\frac{1}{-4\times-4}=\frac{1}{16}$
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