Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review - Page 329: 33

Answer

$\dfrac{x^{2}}{625y^{4}z^{4}}$

Work Step by Step

Using laws of exponents, then, \begin{array}{l} (5xyz)^{-4}(x^{-2})^{-3} \\\\= (5^{-4}x^{-4}y^{-4}z^{-4})(x^{-2(-3)}) \\\\= (5^{-4}x^{-4}y^{-4}z^{-4})(x^{6}) \\\\= 5^{-4}x^{-4+6}y^{-4}z^{-4} \\\\= 5^{-4}x^{2}y^{-4}z^{-4} \\\\= \dfrac{x^{2}}{5^{4}y^{4}z^{4}} \\\\= \dfrac{x^{2}}{625y^{4}z^{4}} .\end{array}
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