Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review: 12

Answer

$\frac{1}{a}$

Work Step by Step

$\frac{a^{16}}{a^{17}}=a^{16-17}=a^{-1}=\frac{1}{a}$
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