Answer
$\frac{1}{2a^{17}}$
Work Step by Step
$\frac{9a(a^{-3})}{18a^{15}}=\frac{9}{18}\times a^{1+(-3)-15}=\frac{1}{2}\times a^{-17}=\frac{1}{2a^{17}}$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 5 - Review - Page 329: 14
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