Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.1 - Sequences - Exercise Set: 32

Answer

$\frac{1}{32}$

Work Step by Step

To calculate $a_n$, we plug in $n$ to the general formula. To calculate the result, we use PEMDAS (parentheses, exponentation, multiplication, division, addition, subtraction) to determine which operation is applied first. $a_{6} = \frac{6-4}{(-2)^{6}} = \frac{6-4}{64} = \frac{2}{64} = \frac{1}{32}$
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