Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.1 - Sequences - Exercise Set: 12

Answer

$\frac{1}{3}, 1, 3, 9, 27$

Work Step by Step

Let's evaluate $a_1, a_2, a_3, a_4, $and $a_5$ by plugging in $1, 2, 3, 4, $ and $5$ for each $n$. $a_1 = 3^(1-2) = 3^{-1} = \frac{1}{3}$ $a_2 = 3^(2-2) = 3^0 = 1$ $a_3 = 3^(3-2) = 3^1 = 3$ $a_4 = 3^(4-2) = 3^2 = 9$ $a_5 = 3^(5-2) = 3^3 = 27$
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