## Intermediate Algebra (6th Edition)

$\frac{1}{4}, \frac{1}{5}, \frac{1}{6}, \frac{1}{7}, \frac{1}{8}$
Let's evaluate $a_1, a_2, a_3, a_4,$and $a_5$ by plugging in $1, 2, 3, 4,$ and $5$ for each $n$. $a_1 = \frac{1}{1+3} = \frac{1}{4}$ $a_2 = \frac{1}{2+3} = \frac{1}{5}$ $a_3 = \frac{1}{3+3} = \frac{1}{6}$ $a_4 = \frac{1}{4+3} = \frac{1}{7}$ $a_5 = \frac{1}{5+3} = \frac{1}{8}$