Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.1 - Sequences - Exercise Set: 16

Answer

$0, -1, 2, -3, 4$

Work Step by Step

Let's evaluate $a_1, a_2, a_3, a_4, $and $a_5$ by plugging in $1, 2, 3, 4, $ and $5$ for each $n$. We use PEMDAS (parentheses, exponentation, multiplication, division, addition, subtraction) to decide which operations go first. \begin{align} a_1 &= (-1)^{1+1}(1-1) = (-1)^2(1-1) = 1 \cdot(1-1) = 1 \cdot 0 = 0\\ \\ a_2 &= (-1)^{2+1}(2-1) = (-1)^3(2-1) = -1\cdot(2-1) = -1 \cdot 1 = -1\\ \\ a_3 &= (-1)^{3+1}(3-1) = (-1)^4(3-1) = 1 \cdot(3-1) = 1 \cdot 2 = 2\\ \\ a_4 &= (-1)^{4+1}(4-1) = (-1)^5(4-1) = -1\cdot(4-1) = -1 \cdot 3 = -3\\ \\ a_5 &= (-1)^{5+1}(5-1) = (-1)^6(5-1) = 1 \cdot(5-1)= 1 \cdot 4 = 4\\ \\ \end{align}
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