Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Review - Page 669: 79

Answer

$40.5$

Work Step by Step

Infinite geometric sequence with first four terms 27, 9, 3, 1 $9/27 = 1/3$ $3/9 = 1/3$ $a_1 = 27$ $r = 1/3$ $S = a_1/(1-r)$ $S = 27/(1-1/3)$ $S = 27/(2/3)$ $S = 27*3/1*3 /(2/3)$ $S = 81/3 /(2/3)$ $S = 81/2$ $S = 40.5$
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