Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Review - Page 669: 78

Answer

$-70$

Work Step by Step

$14-8=6$ $8-2=6$ This arithmetic sequence has a common difference of 6, and we want the 15th term of the sequence. To find the $n$th term of an arithmetic sequence, we use the following formula: $a_n = a_1 + (n-1) * d$ (where $n$ is the $n$th term of the sequence, $a_1$ is the first term of the sequence, and $d$ is the common difference. $a_n = a_1 + (n-1)*d$ $n=15$ $a_1 = 14$ $d=-6$ $a_{15} = 14 + (15-1)*-6$ $a_{15} = 14 +14*-6$ $a_{15} = 14 -84$ $a_{15} = -70$
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