Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.1 Introduction to Factoring - 5.1 Exercise Set: 55

Answer

$(x-6)(2x^2-1)$

Work Step by Step

Using factoring by grouping, the factored form of the given expression, $ 2x^3-12x^2-x+6 ,$ is \begin{array}{l} (2x^3-12x^2)-(x-6) \\\\= 2x^2(x-6)-(x-6) \\\\= (x-6)(2x^2-1) .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.