Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.1 Introduction to Factoring - 5.1 Exercise Set - Page 310: 42

Answer

$(2z+9)(3z^2+1)$

Work Step by Step

Factoring the $GCF= (2z+9) $, the factored form of the given expression, $ 3z^2(2z+9)+(2z+9) ,$ is \begin{align*} (2z+9)(3z^2+1) .\end{align*}
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