Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.1 Introduction to Factoring - 5.1 Exercise Set: 53

Answer

$(6a+7)(a^2+1)$

Work Step by Step

Using factoring by grouping, the factored form of the given expression, $ 6a^3+7a^2+6a+7 ,$ is \begin{array}{l} (6a^3+7a^2)+(6a+7) \\\\= a^2(6a+7)+(6a+7) \\\\= (6a+7)(a^2+1) .\end{array}
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