Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 14 - Sequences, Series, and the Binomial Theorem - 14.4 The Binomial Theorem - 14.4 Exercise Set: 24

Answer

1275

Work Step by Step

$\binom{51}{49}=\frac{51!}{(51-49)!\times49!}=\frac{51!}{2!\times49!}=\frac{49!\times50\times51}{49!\times2!}=\frac{50\times51}{2!}=1275$
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