Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 14 - Sequences, Series, and the Binomial Theorem - 14.4 The Binomial Theorem - 14.4 Exercise Set - Page 922: 21

Answer

1

Work Step by Step

$\binom{9}{9}=\frac{9!}{(9-9)!\times9!}=\frac{9!}{0!\times9!}=\frac{9!}{1\times9!}=1$
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