Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 14 - Sequences, Series, and the Binomial Theorem - 14.4 The Binomial Theorem - 14.4 Exercise Set - Page 922: 20

Answer

56

Work Step by Step

$\binom{8}{5}=\frac{8!}{(8-5)!\times5!}=\frac{8!}{3!\times5!}=\frac{5!\times6\times7\times8}{5!\times3!}=\frac{6\times7\times8}{3!}=56$
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