College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.6 - Factoring - P.6 Exercises: 84

Answer

$(x-3)(x^2+3x+9)$

Work Step by Step

RECALL: A difference of two cubes can be factored using the formula $A^3-B^3=(A-B)(A^2+AB+B^2)$ The given binomial can be written as: $=x^3-3^3$ The binomial is a difference of two cubes. Factor using the formula above with $A=x$ and $B=3$ to obtain: $=(x-3)(x^2+(x)(3)+3^2) \\=(x-3)(x^2+3x+9)$
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