College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.6 - Factoring - P.6 Exercises: 110

Answer

$2(x^{2}+4)^{4}(x-2)^{3}(7x^{2}-10x+8)$

Work Step by Step

Factor out $x^2+4$ and $x-2$: $5(x^{2}+4)^{4}(2x)(x-2)^{4}+(x^{2}+4)^{5}(4)(x-2)^{3}=2(x^{2}+4)^{4}(x-2)^{3}[(5)(x)(x-2)+(x^{2}+4)(2)] =2(x^{2}+4)^{4}(x-2)^{3}(5x^{2}-10x+2x^{2}+8)=2(x^{2}+4)^{4}(x-2)^{3}(7x^{2}-10x+8)$
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