College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.6 - Factoring - P.6 Exercises: 59

Answer

$\frac{(-3x-4)\sqrt[3]{x}}{\sqrt[3]{x-2}}$

Work Step by Step

$2x^{1/3}(x-2)^{2/3}-5x^{4/3}(x-2)^{-1/3}=x^{1/3}(x-2)^{-1/3}[2(x-2)-5x]=x^{1/3}(x-2)^{-1/3}(2x-4-5x)=x^{1/3}(x-2)^{-1/3}(-3x-4)=\frac{(-3x-4)\sqrt[3]{x}}{\sqrt[3]{x-2}}$
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