Answer
$(3a+b^{2})(9a^{2}-3ab^{2}+b^{4})$
Work Step by Step
$27a^{3}+b^{6}=(3a)^{3}+(b^{2})^{3}=(3a+b^{2})[(3a)^{2}-(3a)(b^{2})+(b^{2})^{2}]=(3a+b^{2})(9a^{2}-3ab^{2}+b^{4})$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter P, Prerequisites - Section P.6 - Factoring - P.6 Exercises - Page 43: 94
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