College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.6 - Factoring - P.6 Exercises: 94

Answer

$(3a+b^{2})(9a^{2}-3ab^{2}+b^{4})$

Work Step by Step

$27a^{3}+b^{6}=(3a)^{3}+(b^{2})^{3}=(3a+b^{2})[(3a)^{2}-(3a)(b^{2})+(b^{2})^{2}]=(3a+b^{2})(9a^{2}-3ab^{2}+b^{4})$
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