College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.6 - Factoring - P.6 Exercises: 43

Answer

$(3x+y)(9x^2+3xy+y^2)$

Work Step by Step

RECALL: $A^3+B^3=(A+B)(A^2-AB+B^2)$ The given binomial can be written as: $=3^3x^3+y^3 \\=(3x)^3+y^3$ The binomial above is a sum of two cubes. Factor using the the formula above with $A=3x$ and $B=y$ to obtain: $=(3x+y)[(3x)^2+(3x)(y) +y^2] \\=(3x+y)(9x^2+3xy+y^2)$
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