Answer
$(2+3w)(4+6w+9w^2)$
Work Step by Step
RECALL:
$A^3+B^3=(A+B)(A^2-AB+B^2)$
The given binomial can be written as:
$=2^3+3^3w^3
\\=2^3+(3w)^3$
The binomial above is a sum of two cubes.
Factor using the the formula above with $A=2$ and $B=3w$ to obtain:
$=(2+3w)[2^2+(2)(3w) + (3w)^2]
\\=(2+3w)(4+6w+9w^2)$
