## College Algebra 7th Edition

$(2+3w)(4+6w+9w^2)$
RECALL: $A^3+B^3=(A+B)(A^2-AB+B^2)$ The given binomial can be written as: $=2^3+3^3w^3 \\=2^3+(3w)^3$ The binomial above is a sum of two cubes. Factor using the the formula above with $A=2$ and $B=3w$ to obtain: $=(2+3w)[2^2+(2)(3w) + (3w)^2] \\=(2+3w)(4+6w+9w^2)$