College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.6 - Factoring - P.6 Exercises: 39

Answer

$(x+3)(x^2-3x+9)$

Work Step by Step

RECALL: $A^3+B^3=(A+B)(A^2-AB+B^2)$ The given binomial can be written as: $x^3+3^3$ The binomial above is a sum of two cubes. Factor using the the formula above with $A=x$ and $B=3$ to obtain: $=(x+3)(x^2-x(3) + 3^2) \\=(x+3)(x^2-3x+9)$
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